Java Program to check whether given word is Palindrome or not

This post will explain us, how to implement palindrome logic with different ways, using java.

public class WordPalindrome {
  public static void main(String[] args) {
   String word="LIRIL";
   boolean isPalin = isPalindromeOne(word);
   if(isPalin){
    System.out.println("Given word ["+word+"] is palindrome");
   }else{
    System.out.println("Given word ["+word+"] is not palindrome");
   }
   word = "Hello";
   isPalin = isPalindromeOne(word);
   if(isPalin){
    System.out.println("Given word ["+word+"] is palindrome");
   }else{
    System.out.println("Given word ["+word+"] is not palindrome");
   }
   
  }


  public static boolean isPalindromeOne(String word){
   boolean isPalindrome = false;
   //first way of checking
   char[] array = word.toCharArray();
   char[] newArray = new char[array.length];
   for (int i = 0; i < array.length; i++) {
  char c = array[array.length-i-1];
  newArray[i] =(char)c;
 }
   if(word.equalsIgnoreCase(String.valueOf(newArray))){
    isPalindrome = true;
   }
   //second way of checking
   String reverse ="";
   for (int i = 0; i < word.length(); i++) {
  char c= word.charAt(i);
  reverse = c+reverse;
 }
   if(reverse.equalsIgnoreCase(word)){
    isPalindrome = true; 
   }
   
   
 
   return isPalindrome;
  }
  
  
  
}